(2x-3)/(4x^2-9)

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Solution for (2x-3)/(4x^2-9) equation: 


D( x )

4*x^2-9 = 0

4*x^2-9 = 0

4*x^2-9 = 0

4*x^2 = 9 // : 4

x^2 = 9/4

x^2 = 9/4 // ^ 1/2

abs(x) = 3/2

x = 3/2 or x = -3/2

x in (-oo:-3/2) U (-3/2:3/2) U (3/2:+oo)

(2*x-3)/(4*x^2-9) = 0

2*x-3 = 0 // + 3

2*x = 3 // : 2

x = 3/2

x in { 3/2} 

x belongs to the empty set

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